Murrey Math Esignal EFS Script & Info

MurreyMathAltButtons.efs

There is an official MurreyMath site (http://www.murreymathtrading.com/) which will presumably provide more comprehensive software and instructions for its use. This is simply a freebie EFS script (available in the Esignal EFS library) and some information from Tim Kruzel. Tim Kruzel kindly made this "dissertation" available which provides a thorough discussion of the method and its calculations... and then some. Good Trading!

 

EFS script is here.

 

Murrey Math Study Notes

Written by Tim Kruzel

Introduction

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·                                                 FIGURE 1

Squares

·                TABLE 1:

·                IF (the max value of    AND  (the max value of      THEN (SR is)

·                    the entity is less        the entity is

·                    than or equal to)         greater than)              

·                    250,000                   25,000                100,000

·                     25,000                    2,500                 10,000

·                      2,500                      250                  1,000

·                        250                       25                    100

·                         25                       12.5                   12.5

·                         12.5                      6.25                  12.5

·                          6.25                     3.125                  6.25

·                          3.125                    1.5625                 3.125

·                          1.5625                   0.390625               1.5625

·                          0.390625                 0.0                    0.1953125

Murrey Math Lines

The symbol: MML be defined as: Any Murrey Math Line
The symbol: MMML be defined as: Major Murrey Math Line
The symbol: mMML be defined as: Minor Murrey Math Line
The symbol: bMML be defined as: Baby Murrey Math Line

and, using the abbreviation MMI to mean "Murrey Math Interval", let;

The symbol: MMI be defined as: Any Murrey Math Interval
The symbol: MMMI be defined as: Major Murrey Math Interval = SR/8
The symbol: mMMI be defined as: Minor Murrey Math Interval = SR/8/8
The symbol: bMMI be defined as: Baby Murrey Math Interval = SR/8/8/8

where the symbol /8/8/8 means that SR is to be divided by 8 three times. For example, if SR = 100 then the Baby Murrey Math Interval bMMI is: 100/8/8/8 = 12.5/8/8 = 1.5625/8 = 0.1953125

·                100   --------------------------------------------  8/8  MMML

·                 

·                87.5  --------------------------------------------  7/8  MMML

·                 

·                75    --------------------------------------------  6/8  MMML

·                 

·                62.5  --------------------------------------------  5/8  MMML

·                 

·                50    --------------------------------------------  4/8  MMML

·                 

·                37.5  --------------------------------------------  3/8  MMML

·                 

·                25    --------------------------------------------  2/8  MMML

·                 

·                12.5  --------------------------------------------  1/8  MMML

·                 

·                0     --------------------------------------------  0/8  MMML

·                 

·                                        FIGURE 2

·                75       --------------------------------------------  8/8  mMML

·                 

·                73.4375  --------------------------------------------  7/8  mMML

·                 

·                71.875   --------------------------------------------  6/8  mMML

·                 

·                70.3125  --------------------------------------------  5/8  mMML

·                 

·                68.75    --------------------------------------------  4/8  mMML

·                 

·                67.1875  --------------------------------------------  3/8  mMML

·                 

·                65.625   --------------------------------------------  2/8  mMML

·                 

·                64.0625  --------------------------------------------  1/8  mMML

·                 

·                62.5     --------------------------------------------  0/8  mMML

·                 

·                                        FIGURE 3

Characteristics of MMLs

Rules and Exceptions

For example, suppose a stock is trading within a range of 28 1/4 to 34 1/2. In this case the value of SR is 100. The MMMI is 12.5 (i.e. 100/8). The next smaller MMI is a mMMI = 12.5/8 = 1.5625. The MMML closest to 28 1/4 is the 2/8 th's (i.e. 2 x 12.5 = 25). The closest mMML (measured from 25) is also a 2/8 th's MML (i.e. 2 x 1.5625 = 3.125). So, the bottom of the square is 25 + 3.125 = 28.125 (i.e. 28 1/8).

The 28 1/8 MML is the base of the square in time. This MML satisfies rule 1 (it is an even numbered line, 2/8 th's) and it is close to 28 1/4 (28 1/4 - 28 1/8 = 1/8 = .125). The result of .125 is less than 4/8 th's of the next smaller octave which is a "baby" octave (bMMI = 1.5625/8 = .1953125). Specifically .125 is less than .78125 (4 x .1953125 = .781254).

NOTE: If the bottom MML of the square in time is an even MML, and the top MML of the square in time is 2, 4, or 8 MMI's above the bottom MML, then the top MML is also an even numbered MML.

For example, consider the same stock trading within the range 28 1/4 to 34 1/2. The base of the square in time was identified as the 2/8 th's mMML 28.125. In this case the top of the square is the mMML that is 4 mMMI's above the base: 28.125 + (4 x 1.5625) = 34.375. This MML can also be shown to be "close" to the high end of the trading range, since, 34.5 - 34.375 = .125 and .125 is less than .781254 (4 x .1953125 = .781254). Recall that .1953125 is the bMMI (i.e. the next smaller octave).

An example of this can be seen on Chart #91 in Murrey's book. This is a chart of Chase Manhatten. In this case the bottom and top MML's of the square in time are the 5/8 th's and 7/8 th's MML's respectively. These are obviously odd MML's. Another example of an exception is Chart #83 in Murrey's book. In this case the bottom of the square in time is 37.5 (an odd 3/8 th's line) and the top of the square in time is 62.5 (an odd 5/8 th's line).

"Then you simply count up 2, 4, or 8 lines, and include the top of its trading range, as long as it's no higher than a) 19, b) 39, c) 78 cents above the 100% line. (there are exceptions where it will run up a full 12.5, or 25 or 50% line above the 100% line and come back down..."

Calculating the MMLs -- Example 1

PriceRange = 35.25 - 28.0 = 7.25

Murrey refers to this as "setting the rhythm" or identifying the "perfect square". Refer to TABLE 1 in this paper. Reading from TABLE 1 SR = 100 (This is because the high price for First American was 35.25. Since 35.25 is less than 250 but greater than 25, SR = 100).

Let's define two new parameters. The first parameter is RangeMMI. RangeMMI = PriceRange/MMI. RangeMMI measures the price range of First American (or any entity) in units of Murrey Math Intervals (MMI's).

The second parameter is OctaveCount. The purpose of OctaveCount will become evident shortly. The question to answer is, "What MMI should be used for creating the square in time?" This question will be answered by dividing the SR value by 8 until the "appropriate MMI" is found. So:

MMI = MMMI = SR/8 = 100/8 = 12.5

This is a MMMI. Is this the "appropriate MMI"? To answer that question divide PriceRange by this MMI.

RangeMMI = PriceRange/MMI = 7.25/12.5 = 0.58

Now compare RangeMMI to 1.25. If RangeMMI is less than 1.25 then a smaller MMI is needed. This is indeed the case because 0.58 is less than 1.25. Since the first MMI calculated was a MMMI, then the next MMI will be a mMMI. Simply divide the prior MMI by 8 to get the new MMI.

MMI = mMMI = MMMI/8 = 1.5625

This is a mMMI. Is this the "appropriate MMI"? To answer that question divide PriceRange by this latest MMI.

RangeMMI = PriceRange/MMI = 7.25/1.5625 = 4.64

Now compare RangeMMI to 1.25. If RangeMMI is less than 1.25 then a smaller MMI is needed. Since RangeMMI is 4.64 and 4.64 is greater than 1.25 we're done. The correct MMI to use is the mMMI which is 1.5625. (Naturally, in other cases, this process may be repeated further, continuing division by 8, until RangeMMI is greater than 1.25.)

Since we had to divide the perfect square (SR) by 8 two times to arrive at the appropriate MMI (SR/8/8 = 100/8/8 = 12.5/8 = 1.5625) we'll set the value of OctaveCount to be 2. The value of OctaveCount will act as a reminder as we proceed through this example.

Now the question of 1.25. Where did this number come from? Partly trial and error and partly reasoning. Remember that the parameter RangeMMI describes the trading range of First American in units of Murrey Math Intervals. Remember also that the rules for the square in time require that the square be at least 2 MMI's high, and that the square be close to the high and low values of the trading range.

If we used the MMMI to build the square in time for First American the result would have been a square with a height of (2 x 12.5) 25. Because First American has only traded within a range of 7.25 points, this square would not represent First American's' behavior very well. The trading range of First American should approximately fill the square. By choosing a smaller MMI (i.e. mMMI = 1.5625) the result is a square in time that will be 4 MMI's high (RangeMMI = 4.64 which is rounded to 4. The actual height selected for the square in time will be determined in STEP 4). Again, recall the rule that the square must be 2, 4, or 8 MMI's high. (Is the number 1.25 perfect? NO! But, tests conducted on the charts in the Murrey Math book indicate that 1.25 works in nearly all cases).

In STEP 3 above, we selected the appropriate value for the MMI and calculated the final value of RangeMMI. Given the value of RangeMMI, TABLE 2 may be used to select the actual height of the square in time.

TABLE 2

ALLOWED SQUARES IN TIME:

RangeMMI                Square in Time is Bounded by These MML's

 

1.25 < RangeMMI < 3.0   (0,2) (1,3) (2,4) (3,5) (4,6) (5,7) (6,8) (7,1)

3.0 <= RangeMMI < 5.0   (0,4) (2,6) (4,8) (6,2)

5.0 <= RangeMMI < ...   (0,8) (4,4)

TABLE 2 was arrived at using trial and error. The results of the C program I had written were compared to the charts in the back of the Murrey Math book. Is TABLE 2 perfect? NO! But it works fairly well. TABLE 2 specifies the allowed upper and lower MML numbers that may be used to create the square in time. Note that once the upper and lower MML's are specified so is the height of the square. TABLE 2 attempts to accomodate Murrey's rules for creating the square in time as well as the exceptions to those rules.

The first row of TABLE 2 addresses squares that are two MMI's high. Note that the exception of having squares in time with odd top and bottom MML's is included.

The second row of TABLE 2 addresses squares that are four MMI's high. Note that these squares are required to lie on even MML's only.

The third row of TABLE 2 addresses squares that are eight MMI's high. Note that these squares are required to lie on (0,8) or (4,4) MML's only. The notation (0,8) means that the bottom of the square will be a 0/8 th's MML and the top of the square will be an 8/8 th's MML.

Continuing with First American, recall that RangeMMI = 4.64. Reading from TABLE 2 we see that the square in time will be 4 MMI's high and will lie on one of the MML combinations (0,4), (2,6), (4,8), or (6,2).

The objective of this step is to find the MML that is closest to the low value of First American's trading range (i.e. 28.0). This MML must be a mMML since the MMI we are using is a mMMI (i.e. 1.5625). Actually, the MML we will find in this step is the mMML that is closest to but is less than or equal to First American's low value.

This is fairly simple. To repeat, the MML type must correspond to the MMI type that was selected. We chose an MMI that is a mMMI (i.e. 1.5625), hence, the MML must be a mMML. We now make use of the parameter OctaveCount. In this example, OctaveCount = 2. Since OctaveCount = 2 we will perform 2 divisions by 8 to arrive at the desired MML.

MMI = MMMI = SR/8 = 100/8 = 12.5

The base of the perfect square is 0.0, so subtract the base from the low value of First American's trading range (28.0 - 0.0 = 28.0). Now we find the MMML that is less than or equal to 28.0. In other words, how many MMMI's could we stack up from the base (i.e. 0.0) to get close to (but less than 28.0).

28.0/MMMI = 28.0/12.5 = 2.24 ==> 2 (Since there are no partial MMI's)

0.0 + (2 x 12.5) = 25.0
25.0 is the 2/8 th's MMML that is closest to but less than 28.0

Since OctaveCount = 2, this process will be repeated a second time for the mMMI. The only difference is that the base line is the MMML from the prior step. So, once again, subtract the base (i.e. 25) from the low value of First American's trading range (28 - 25 = 3.0). Now find the mMML that is less than or equal to 28.0. In other words, how many mMMI's could we stack up from the base (i.e. 25) to get close to (but less than 28.0).

3.0/mMMI = 3.0/1.5625 = 1.92 ==> 1 (Since there are no partial MMI's)

25 + (1 x 1.5625) = 26.5625
26.5625 is the 1/8 th mMML that is closest to but less than 28.0

So, mMML = 26.5625

This mMML is the "best first guess" for the bottom of the square in time. But there is a problem...

By the end of STEP 5, a square in time has been defined that will be 4 mMMI's in height and have a base on the 1/8 th mMML = 26.5625. Recall, however, that the rules in TABLE 2 state that a square that is 4 MMI's in height must lie on an even numbered MML. A 1/8 th line is odd. So, two choices are available. Referring to TABLE 2 we can choose either a (0,4) square or a (2,6) square. Which do we choose?

Let's define an error function and choose the square that minimizes this error. The error function is:

Error = abs(HighPrice - TopMML) + abs(LowPrice - BottomMML)

Where:

Having now defined an error function it can now be applied to the problem at hand. The square in time that was determined in STEP 5 has a bottom MML of 26.5625 and a height of 4 mMMI's. The top MML is therefore 26.5625 + (4 x 1.5625) = (26.5625 + 6.25) = 32.8125. Recall, however, this is still the square lying upon the 1/8 mMML (a (1,5) square on odd MML's). We want to use the error function to distinguish between the (0,4) square and the (2,6) square.

The (0,4) square is simply the (1,5) square shifted down by one mMMI and the (2,6) square is the (1,5) square shifted up by one mMMI.

0/8 th mMML = 26.5625 - 1.5625 = 25.0
4/8 th's mMML = 32.8125 - 1.5625 = 31.25

So, the bottom of the (0,4) square is 25.0 and the top of the (0,4) square is 31.25.

Likewise for the (2,6) square:

2/8 th's mMML = 26.5625 + 1.5625 = 28.125
6/8 th's mMML = 32.8125 + 1.5625 = 34.375

So, the bottom of the (2,6) square is 28.125 and the top of the (2,6) square is 34.375.

Now apply the error function to each square to determine "the best square in time".

Error(0,4) = abs(35.25 - 31.25) + abs(28.0 - 25.0) = 7.0

Error(2,6) = abs(35.25 - 34.375) + abs(28.0 - 28.125) = 1.0

Clearly the (2,6) square is the better fit (has less error). Finally, we have arrived at a square in time that satisfies all of the rules. We can now divide the height of the square by 8 to arrive at the 1/8 lines for the square in time.

(34.375 - 28.125)/8 = 6.25/8 = .78125

So the final square is:

                         100.0%   34.375

                          87.5%   33.59375

                          75.0%   32.8125

                          62.5%   32.03125

                          50.0%   31.25

                          37.5%   30.46875

                          25.0%   29.6875

                          12.5%   28.90625

                           0.0%   28.125

Exactly as seen on Chart #85B of the Murrey Math book.

Calculating the MMLs -- Example 2

PriceRange = 437.5 - 433.5 = 4.0

Refer to TABLE 1: SR = 1000

Octave 1:

Octave 2:

Octave 3:

Since the scale factor SR was divided by 8 three times, OctaveCount = 3.

Refer to TABLE 2: RangeMMI = 2.048 so the height of the square is 2.

First Octave:

Second Octave:

Third Octave:

This results in a square with a height of 2 bMMI's and a base on the 5/8 th's bMML 431.64.

The result of STEP 5 is a square with a height of 2 bMMI's and a base on the 5/8 th's bMML 431.64. Refer to TABLE 2: The likely "best square" is either the (5,7) or the (6,8).

The bottom and top of the (5,7) square are:
Bottom: 431.64
Top: 431.64 + (2 x 1.953125) = 435.55

The bottom and top of the (6,8) square are:
Bottom: 431.64 + 1.953125 = 433.59
Top: 435.55 + 1.953125 = 437.50

Calculate the fit errors:

The "best square" is the (6,8) square since the (6,8) square has the smallest error.

So the final square is:

                         100.0%   437.5

                          87.5%   437.01

                          75.0%   436.52

                          62.5%   436.03

                          50.0%   435.54

                          37.5%   435.05

                          25.0%   434.57

                          12.5%   434.08

                           0.0%   433.59

Calculating the MMLs -- Example 3

PriceRange = 7170 - 7110 = 60.0

Refer to TABLE 1: SR = 10000

Octave 1:

Octave 2:

Octave 3:

Since the scale factor SR was divided by 8 three times, OctaveCount = 3.

Refer to TABLE 2: RangeMMI = 3.072 so the height of the square is 4.

First Octave:

Second Octave:

Third Octave:

This results in a square with a height of 4 bMMI's and a base on the 4/8 th's bMML 7109.375.

The result of STEP 5 is a square with a height of 4 bMMI's and a base on the 4/8 th's bMML 7109.375. Refer to TABLE 2: The likely "best square" is the (4,8). One could, of course, perform a test using the error function and check other squares as was done in the prior examples. A quick visual check of Chart #300, however, shows that the (2,6) or (6,2) squares will result in errors that are greater than the error associated with the (4,8) square.

The bottom and top of the (4,8) square are:
Bottom: 7109.375
Top: 7109.375 + (4 x 19.53125) = 7187.5

Since the original price values were multiplied by 10000, the reverse operation is performed to arrive at MML values that match the quoted prices of the Deutsche Mark.

The "corrected" bottom and top of the (4,8) square are:
Bottom: .7109
Top: .7187

So the final square is:

                         100.0%   .7187

                          87.5%   .7177

                          75.0%   .7168

                          62.5%   .7158

                          50.0%   .7148

                          37.5%   .7138

                          25.0%   .7129

                          12.5%   .7119

                           0.0%   .7109

Calculating the MMLs -- Example 4

PriceRange = 10275 - 10205 = 70.0

Refer to TABLE 1: SR = 10000

Octave 1:

Octave 2:

Octave 3:

Since the scale factor SR was divided by 8 three times, OctaveCount = 3.

Refer to TABLE 2: RangeMMI = 3.584 so the height of the square is 4.

First Octave:

Second Octave:

Third Octave:

This results in a square with a height of 4 bMMI's and a base on the 2/8 th's bMML 10195.3125.

The result of STEP 5 is a square with a height of 4 bMMI's and a base on the 2/8 th's bMML 10195.3125. Refer to TABLE 2: The likely "best square" is the (2,6). One could, of course, perform a test using the error function and check other squares as was done in the prior examples. A quick visual check of Chart #298, however, shows that the (0,4) or (4,8) squares will result in errors that are greater than the error associated with the (2,6) square.

The bottom and top of the (4,8) square are:
Bottom: 10195.3125
Top: 10195.3125 + (4 x 19.53125) = 10273.4375

Since the original price values were multiplied by 100, the reverse operation is performed to arrive at MML values that match the quoted prices of the 30 Yr Bond.

The "corrected" bottom and top of the (4,8) square are:
Bottom: 101.95
Top: 102.73

So the final square is:

                         100.0%   102.73

                          87.5%   102.63

                          75.0%   102.54

                          62.5%   102.44

                          50.0%   102.34

                          37.5%   102.24

                          25.0%   102.15

                          12.5%   102.05

                           0.0%   101.95

Calculating the MMLs -- Example 5

PriceRange = 32.75 - 26.75 = 6.0

Refer to TABLE 1: SR = 100

Octave 1:

Octave 2:

Since the scale factor SR was divided by 8 two times, OctaveCount = 2.

Refer to TABLE 2: RangeMMI = 3.84 so the height of the square is 4.

First Octave:

Second Octave:

This results in a square with a height of 4 mMMI's and a base on the 1/8 th's mMML 26.5625

The result of STEP 5 is a square with a height of 4 mMMI's and a base on the 1/8 th's mMML 26.5625. Refer to TABLE 2: Two squares are candidates for the "best square", the (0,4) square and the (2,6) square.

The bottom and top of the (0,4) square are:
Bottom: 26.5625 - 1.5625 = 25.0
Top: 25.0 + (4 x 1.5625) = 31.25

The bottom and top of the (2,6) square are:
Bottom: 26.5625 + 1.5625 = 28.125
Top: 28.125 + (4 x 1.5625) = 34.375

Now apply the error function to each square to determine "the best square in time".

Error(0,4) = abs(32.75 - 31.25) + abs(26.75 - 25.0) = 3.25

Error(2,6) = abs(32.75 - 34.375) + abs(26.75 - 28.125) = 3.0

The (2,6) square has the smallest error and one would expect it to be the square of choice. Refer to Chart #85 in the Murrey Math book. The square selected in the book was the (0,4) square.

Other Considerations When Selecting the MMLs

Error(0,4) = abs(32.75 - 31.25) + abs(26.75 - 25.0) = 3.25
Error(2,6) = abs(32.75 - 34.375) + abs(26.75 - 28.125) = 3.0

Mapping of Murrey Math Lines

·                                            TABLE 3

·                 

·                # of MMI's

·                in Square     0.0%  12.5%  25%  37.5%  50%  62.5%  75%  87.5%  100%

·                 

·                     2        0/8   2/8s  4/8s  6/8s   1/8  2/8s   4/8s  6/8s  2/8

·                     2        1/8   2/8s  4/8s  6/8s   2/8  2/8s   4/8s  6/8s  3/8

·                     2        2/8   2/8s  4/8s  6/8s   3/8  2/8s   4/8s  6/8s  4/8

·                     2        3/8   2/8s  4/8s  6/8s   4/8  2/8s   4/8s  6/8s  5/8

·                **   2        4/8   2/8s  4/8s  6/8s   5/8  2/8s   4/8s  6/8s  6/8

·                     2        5/8   2/8s  4/8s  6/8s   6/8  2/8s   4/8s  6/8s  7/8

·                     2        6/8   2/8s  4/8s  6/8s   7/8  2/8s   4/8s  6/8s  8/8

·                     2        7/8   2/8s  4/8s  6/8s   8/8  2/8s   4/8s  6/8s  1/8

·                 

·                     4        0/8   4/8s  1/8   4/8s   2/8  4/8s   3/8   4/8s  4/8

·                     4        2/8   4/8s  3/8   4/8s   4/8  4/8s   5/8   4/8s  6/8

·                     4        4/8   4/8s  5/8   4/8s   6/8  4/8s   7/8   4/8s  8/8

·                     4        6/8   4/8s  7/8   4/8s   8/8  4/8s   1/8   4/8s  2/8

·                 

·                     8        0/8   1/8   2/8   3/8    4/8   5/8   6/8   7/8   8/8

·                     8        2/8   3/8   4/8   5/8    6/8   7/8   8/8   1/8   2/8

·                     8        4/8   5/8   6/8   7/8    8/8   1/8   2/8   3/8   4/8

·                     8        6/8   7/8   8/8   1/8    2/8   3/8   4/8   5/8   6/8

Gann Minor 50% Lines, and 19- & 39-cent Reversals

Time

Circles of Conflict

The Square in Time

·                TABLE 4: TRENDLINES

·                 Line     Line           Points Forming the Line:

·                 Trend    Slope          Point 1          Point 2

·                   +       8:8             O                X

·                   +       8:7             O                G'

·                   +       8:6             O                F'

·                   +       8:5             O                E'

·                   +       8:4             O                D'

·                   +       8:3             O                C'

·                   +       8:2             O                B'

·                   +       8:1             O                A'

·                   +       1:8             O                Q

·                   +       2:8             O                R

·                   +       3:8             O                S

·                   +       4:8             O                T

·                   +       5:8             O                U

·                   +       6:8             O                V

·                   +       7:8             O                W

·                   -       8:8             O'               P

·                   -       8:7             O'               G

·                   -       8:6             O'               F

·                   -       8:5             O'               E

·                   -       8:4             O'               D

·                   -       8:3             O'               C

·                   -       8:2             O'               B

·                   -       8:1             O'               A

·                   -       1:8             O'               W

·                   -       2:8             O'               V

·                   -       3:8             O'               U

·                   -       4:8             O'               T

·                   -       5:8             O'               S

·                   -       6:8             O'               R

·                   -       7:8             O'               Q

·                 

·                 

·                TABLE 5: MOMENTUM LINES

·                 Line     Line           Points Forming the Line:

·                 Trend    Slope          Point 1          Point 2

·                   +       1:1             G                Q

·                   +       2:2             F                R

·                   +       3:3             E                S

·                   +       4:4             D                T

·                   +       5:5             C                U

·                   +       6:6             B                V

·                   +       7:7             A                W

·                   +       8:8             O                X

·                   +       7:7             G'               Q'

·                   +       6:6             F'               R'

·                   +       5:5             E'               S'

·                   +       4:4             D'               T'

·                   +       3:3             C'               U'

·                   +       2:2             B'               V'

·                   +       1:1             A'               W'

·                   -       1:1             G'               W

·                   -       2:2             F'               V

·                   -       3:3             E'               U

·                   -       4:4             D'               T

·                   -       5:5             C'               S

·                   -       6:6             B'               R

·                   -       7:7             A'               Q

·                   -       8:8             O'               P

·                   -       7:7             G                W'

·                   -       6:6             F                V'

·                   -       5:5             E                U'

·                   -       4:4             D                T'

·                   -       3:3             C                S'

·                   -       2:2             B                R'

·                   -       1:1             A                Q'

·                 

·                 

·                 O'     A'     B'     C'     D'     E'     F'     G'    

·                  ------|------|------|------|------|------|------|-------  X  8/8

·                 |                                                        |

·                 | W'                                                     | W  7/8

·                 |                                                        |

·                 | V'                                                     | V  6/8

·                 |                                                        |

·                 | U'                                                     | U  5/8

·                 |                                                        |

·                 | T'                                                     | T  4/8

·                 |                                                        |

·                 | S'                                                     | S  3/8

·                 |                                                        |

·                 | R'                                                     | R  2/8

·                 |                                                        |

·                 | Q'                                                     | Q  1/8

·                 |                                                        |

·                  ------|------|------|------|------|------|------|-------  P  0/8

·                 O      A      B      C      D      E      F      G     

·                 0/8    1/8    2/8    3/8    4/8    5/8    6/8    7/8     8/8

·                 TIME ===>

·                                          FIGURE 4

No One Ever Went Broke Taking a Profit

·                       1/8 th  + .78 cents 50% of the time = 2.34

·                       2/8 ths (3.125)     75% of the time = 3.12

·                       3/8 ths (4.68)      85% of the time = 4.68

·                       4/8 ths (6.25)      90% of the time = 6.25

·                       5/8 ths (7.81)      95% of the time = 7.81

·                       If Price Moves By:          The probability of reversal is:

·                       (1 x mMMI) + (4 x bMMI)         50%

·                       (2 x mMMI)                      75%

·                       (3 x mMMI)                      85%

·                       (4 x mMMI)                      90%

·                       (5 x mMMI)                      95%

 

Murrey Math Reversal Percentage Moves

·                Price Percentage Moves for Indexes over 500 but under 1000.

·                (Intraday Basis) (Slow Day).

·                 

·                One of the entries is this listing is:

·                 

·                6/8 ths 85% of the time 1.4648

((((1000/8) /8) /8) /8) = 1000/4096 = 0.244140625

Fractals

·                     ----------------------------------------------------------------

·                    |       |       |                |                               |

·                    |       |       |                |                               |

·                    |-------|-------|                |                               |

·                    |       |       |                |                               |

·                    |       |       |                |                               |

·                    |---------------|----------------|                               |

·                    |               |                |                               |

·                    |               |                |                               |

·                    |               |                |                               |

·                    |               |                |                               |

·                    |               |                |                               |

·                    |--------------------------------|-------------------------------|

·                    |                                |                               |

·                    |                                |                               |

·                    |                                |                               |

·                    |                                |                               |

·                    |                                |                               |

·                    |                                |                               |

·                    |                                |                               |

·                    |                                |                               |

·                    |                                |                               |

·                    |                                |                               |

·                    |                                |                               |

·                    |                                |                               |

·                     ----------------------------------------------------------------

·                                                  FIGURE 1

Fractional Brownian Motion

EQ 1: < (X(t2) - X(t1)) ^ 2 > = k*((t2 - t1) ^ (2*H))

o                                    A         B              C           D

o                      

o                            1    X(9:33)   X(10:21)   COL_B - COL_A   COL_C ^2

o                            2    X(9:34)   X(10:22)   COL_B - COL_A   COL_C ^2

o                            3    X(9:35)   X(10:23)   COL_B - COL_A   COL_C ^2

o                            .

o                            .

o                            .

o                            R    X(2:21)   X(3:09)    COL_B - COL_A   COL_C ^2

So < (X(t2) - X(t1)) ^ 2 > would be the sum of all the numbers in Column D divided by the number of samples (R). Where COL_A, COL_B, and COL_C denote the numbers in Column A, Column B, and Column C respectively.

Statistical Nature of Price Changes

| X(t2) - X(t1) |

Where the | | symbol means to take the absolute value of the number inside the vertical brackets. This just means that if X(t2) - X(t1) happens to be a negative number, then ignore the minus sign. Treat the number as if it was positive.

·                       | P(X12)                        *

·                       |                            *|||||*

·                       |                           *|||||||*

·                       |                          *|||||||||*

·                       |                         *|||||||||||*

·                       |                        *|||||||||||||*

·                       |                       *|||||||||||||||*

·                       |                      *|||||||||||||||||*

·                       |                     *|||||||||||||||||||*

·                       |                    *|||||||||||||||||||||*

·                       |                   *|||||||||||||||||||||||*

·                       |                 *|||||||||||||||||||||||||||*

·                       |              *  |||||||||||||||||||||||||||||  *

·                       |          *      |||||||||||||||||||||||||||||      *

·                       |      *          |||||||||||||||||||||||||||||           *

·                       |*                |||||||||||||||||||||||||||||                 *

·                        -----------------------------------------------------------------

·                                      -z * S                      +z * S              X12

·                                                   FIGURE 2A

·                 

·                 

·                       | P(X12)                        *

·                       |                            *     *

·                       |                           *       *

·                       |                          *         *

·                       |                         *           *

·                       |                        *             *

·                       |                       *               *

·                       |                      *                 *

·                       |                     *                   *

·                       |                    *                     *

·                       |                   *                       *

·                       |                 *                           *

·                       |              *                                 *

·                       |          *                                         *

·                       |      *                                                  *

·                       |*||||||                                                  ||||||*

·                        -----------------------------------------------------------------

·                           -z * S                                             +z * S  X12

·                                                   FIGURE 2B

X12 = X(t2) - X(t1)

1.0 - Shaded Area = Unshaded Area

(S ^ 2) = < (X(t2) - X(t1)) ^ 2 > = k*((t2 - t1) ^ (2*H))

EQ 1: < (X(t2) - X(t1)) ^ 2 > = k*((t2 - t1) ^ (2*H))

Assumptions 1 and 2 are pretty good assumptions. Together, these two assumptions make up the random walk model of markets (When H = 1/2). Some have questioned whether or not (X(t2) - X(t1)) is normally distributed. In general, however, the normal distribution is considered to be a good approximation.

This assumption is the basis of Murrey Math. Rejecting this assumption would require the rejection of Murrey Math.

This is a big assumption, but an argument may be made in favor of it. The Square in Time is a fractal. The rules for changing the scale of this fractal are to simply multiply the height and width of the square by 2 or by 1/2. This is a linear scaling. This can only be valid if H = 1.0. H relates the typical change in price < (X(t2) - X(t1)) > to the time interval (t2 - t1) i.e.

< (X(t2) - X(t1)) > is proportional to ((t2 - t1) ^ H)

The same statistical properties should be observed in a larger Square in Time as well as in a smaller Square in Time. This is the statistical self similarity property of price-time behavior. If we wished to consider price action over a longer time frame then we would multiply the time interval by 2.0 (this is how we scale the fractal). Lets do that:

((2 * (t2 - t1)) ^ H) = (2 ^ H) * ((t2 - t1) ^ H)

Note the term (2 ^ H). This term shows that if the time interval is doubled, then one would have to multiply the price range by (2 ^ H). If the scaling rule of the Square in Time is valid then H must be 1.0. Otherwise, we could not simply double price and double time when scaling the Square in Time.

I have no argument for this assumption other than convenience and wishful thinking. One has to start somewhere. This assumption may be valid based upon the way the Square in Time is defined. There may be a theoretical observation that could be used to prove k = 1.0 as was done for assumption (4) showing that H = 1.0. Algorithms are available for identifying the value of k. This would, however, require some computer programming that I do not have the time to perform currently. So, for now, k = 1.0.

(S ^ 2) = < (X(t2) - X(t1)) ^ 2 > = k*((t2 - t1) ^ (2*H))

Setting H = 1.0 and k = 1.0 yields:

(S ^ 2) = < (X(t2) - X(t1)) ^ 2 > = ((t2 - t1) ^ 2)
or
S = t2 - t1

with changes in X and t (price and time) expressed in units of 1/8'ths. Let's represent a change in X (price) using M/8 and let's represent a change in t (time) using N/8, where
M = 1, 2, 3, 4, 5, 6, 7, or 8
N = 1, 2, 3, 4, 5, 6, 7, or 8

z = (M/8)/(N/8) = M/N

·                 PRICE

·                   M   ^

·                       |

·                   8   |  .999    .999    .992   .954    .890    .816    .746    .683

·                       |

·                   7   |  .999    .999    .980   .920    .838    .757    .683    .621

·                       |

·                   6   |  .999    .997    .954   .866    .770    .683    .610    .547

·                       |

·                   5   |  .999    .988    .905   .789    .683    .593    .522    .471

·                       |

·                   4   |  .999    .954    .816   .683    .576    .497    .431    .383

·                       |

·                   3   |  .997    .866    .683   .547    .451    .383    .332    .296

·                       |

·                   2   |  .954    .683    .497   .383    .311    .259    .228    .197

·                       |

·                   1   |  .683    .383    .259   .197    .159    .135    .111    .103

·                        -------------------------------------------------------------->

·                        N   1       2       3      4       5       6       7       8

·                                                                                   TIME

·                                                TABLE 1

·                                           (A SQUARE OF 64)

General Discussion

(change in price)/(change in time) = M/N